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5y^2-33y=52=0
We move all terms to the left:
5y^2-33y-(52)=0
a = 5; b = -33; c = -52;
Δ = b2-4ac
Δ = -332-4·5·(-52)
Δ = 2129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-\sqrt{2129}}{2*5}=\frac{33-\sqrt{2129}}{10} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+\sqrt{2129}}{2*5}=\frac{33+\sqrt{2129}}{10} $
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